Table of Contents
Quant Quiz SBI CLERK MAINS & RBI ASSISTANT MAINS
Quant Quiz to improve your Quantitative Aptitude for SBI Po & SBI clerk exam IBPS PO Reasoning , IBPS Clerk Reasoning , IBPS RRB Reasoning, LIC AAO ,LIC Assistant and other competitive exams
Direction (1 -5) : Each of the following question is followed by two equations (I) & (II). You have to solve each equation and mark answer as per instructions.
Q1.
1. x > y
2. x = y or no relation can be established
3. x ≤ y
4. x < y
5. x ≥ y
Q2.
1. x ≤ y
2. x > y
3. x ≥ y
4. x < y
5. x = y or no relation can be established
Q3.
1. x = y or no relation can be established
2. x ≤ y
3. x < y
4. x > y
5. x ≥ y
Q4.
1. x ≤ y
2. x > y
3. x ≥ y
4. x < y
5. x = y or no relation can be established
Q5.
1. x ≥ y
2. x > y
3. x ≤ y
4. x = y or no relation can be established
5. x < y
Q6. A man invested Rs. (X) at the rate of (R)% p.a. on simple interest for two years and Rs. (X – 400) at the rate of (R + 7.5)% on compound interest for one year. If ratio of total simple interest to total compound interest gets by man is 11 : 8, then what will be possible value of (X) & (R)?
1. 2400 & 12.5
2. 1400 & 10
3. 4400 & 15
4. 4400 & 12.5
5. 8000 & 7.5
Q7. Ayush invested Rs. x, While Veer invested 20% more amount then Ayush and he left the business after eight months, while Anurag joined them after some month with capital of Rs. 600 more than Veer. If profit share of Anurag is Rs. 3000 out of total profit of Rs. 7500 after one year, then what will value ‘x’ and time for Anurag invested?
1. 2500 Rs. & 10 months
2. 3000 Rs. & 10 months
3. 2400 Rs. & 8 months
4. 2000 Rs. & 10 months
5. 2800 Rs. & 8 months
Q8. There are 11 bags numbered 1, 2, 3, ………., up to 11. Each bag is to be filled with either red balls or either blue balls such that at least one bag contains blue balls and the bags containing blue balls are alternatively numbered. Find number of ways in which it can be done?
1. 32
2. 48
3. 64
4. 36
5. 28
Q9. Present age of Tanya and Deepak is in the ratio of______ respectively and present age of Deepak is _______ % more than present age of Shivam. Present average age of Tanya, Deepak and Shivam is 18 years. Present age of Tanya is _________ years.
Which of following options will satisfy the given fill in the blanks respectively.
(I) 5 : 12, 20%, 10 years
(II) 3 : 7, 20% 21 years
(III) 3 : 5, 25%, 13 years 6 months
Which of following options will satisfy the given fill in the blanks respectively.
(I) 5 : 12, 20%, 10 years
(II) 3 : 7, 20% 21 years
(III) 3 : 5, 25%, 13 years 6 months
1. Only (I)
2. Only (III)
3. Only (I) & (II)
4. Only (i) & (III)
5. None of these
Q10. X² women can do a piece of work in 700 days and Y² women can do the same piece of work in 252 days. In how many days (4X × 3Y) women will do two times of same piece of work?
1. 70 days
2. 35 days
3. 28 days
4. 84 days
5. None of these
Solutions
Q1. Ans(2)
Q2. Ans(5)
Q3. ANs(3)
Q4. Ans(1)
Q5. Ans(5)
Q6. Ans(4)
Q7. Ans(1)
Q8. Ans(4)
Case I – If only one bag contains blue balls, then it can be one of the 11 bags and number of ways = 11
Case II – if only two bags contains blue balls, then bags which can have blue balls will be, (1, 3) or (2, 4) or (3, 5) or …. (9, 11)
So, number of ways = 9
Case III – If only 3 bags contains blue balls, then bags which can have blue balls will be, (1, 3, 5) or (2, 4, 6) or (3, 5, 7), …. Or (7, 9, 11)
So, number of ways = 7
Case IV – If only four bags contains blue balls, then bags which can have blue balls be (1, 3, 5, 7) or (2, 4, 6, 8) or ………. (5, 7, 9, 11)
So, number of ways = 5
Case V – If only five bags contain blue balls, then bags which can have blue balls be (1, 3, 5, 7, 9) or (2, 4, 6, 8, 10) or (3, 5, 7, 9, 11)
So, number of ways = 3
Case VI – If only 6 bags contains blue balls, then bag which can have blue balls be (1, 3, 5, 7, 9, 11)
So, number of ways = 1
So, total number of required ways = (11 + 9 + 7 + 5 + 3 + 1) = 36
Case II – if only two bags contains blue balls, then bags which can have blue balls will be, (1, 3) or (2, 4) or (3, 5) or …. (9, 11)
So, number of ways = 9
Case III – If only 3 bags contains blue balls, then bags which can have blue balls will be, (1, 3, 5) or (2, 4, 6) or (3, 5, 7), …. Or (7, 9, 11)
So, number of ways = 7
Case IV – If only four bags contains blue balls, then bags which can have blue balls be (1, 3, 5, 7) or (2, 4, 6, 8) or ………. (5, 7, 9, 11)
So, number of ways = 5
Case V – If only five bags contain blue balls, then bags which can have blue balls be (1, 3, 5, 7, 9) or (2, 4, 6, 8, 10) or (3, 5, 7, 9, 11)
So, number of ways = 3
Case VI – If only 6 bags contains blue balls, then bag which can have blue balls be (1, 3, 5, 7, 9, 11)
So, number of ways = 1
So, total number of required ways = (11 + 9 + 7 + 5 + 3 + 1) = 36
Q9. Ans(4)
Q10. Ans(1)
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