# IBPS PO Quantitative Aptitude Quiz- 2

## IBPS PO Quantitative Aptitude Quiz

Quantitative Aptitude is the most significant part of almost all competitive exams. Candidates appear to be having difficulty with Quantitative Aptitude Questions, so they need to practice more. Even if the portion is difficult, if you practice enough questions and learn the basic concepts, you can surely do well. In this article, we have come up with the IBPS PO Quantitative Aptitude Quiz to enhance your preparation. This IBPS PO Quantitative Aptitude Quiz will assist you to cope with the tough competition. This IBPS PO Quantitative Aptitude Quiz is available to you at no cost. Through this IBPS PO Quantitative Aptitude Quiz, you will learn formulas and short tricks to solve the Quantitative Aptitude Questions. Candidates must solve this IBPS PO Quantitative Aptitude Quiz to improve their exam preparation.

Directions (1-5): Solve the following equations and mark the correct option given below.

1. I. x² – 20x + 91 = 0
II. y² – 32y + 247 = 0
(a) if x<y
(b) if x>y
(c) if x≤y
(d) if x≥y
(e) if x=y or no relation can be established

Ans. c
Exp. I. x² – 20x + 91 = 0
x² – 13x – 7x + 91 = 0
x (x – 13) – 7(x- 13) =0
(x -7) (x- 13) = 0
x=7,13
II. y² – 32y + 247 = 0
y² – 19y – 13y +247 = 0
y (y – 19) – 13(y-19) = 0
(y – 13) (y- 19) = 0
y= 13,19
x≤y

2. I. x² + 19x + 84 = 0
II. y² – 25y + 156 = 0
(a) if x<y
(b) if x>y
(c) if x≤y
(d) if x≥y
(e) if x=y or no relation can be established

Ans. a
Exp. I. x² + 19x + 84 = 0
x² + 12x + 7x + 84 = 0
x (x +12) + 7(x+12) =0
(x +7) (x+ 12) = 0
x=-7,-12
II. y² – 25y + 156 = 0
y² – 12y – 13y +156 = 0
y (y – 12) – 13(y-12) = 0
(y – 13) (y- 12) = 0
y= 13,12
x<y

3. I. x² – 4 = 0
II. y² + 6y + 9 = 0
(a) if x<y
(b) if x>y
(c) if x≤y
(d) if x≥y
(e) if x=y or no relation can be established

Ans. b
Exp. I. x² – 4 = 0
x² =4
x = 2, –2
II. y² +6y + 9 = 0
y2 + 3y + 3y + 9 =0
y (y + 3) + 3(y+ 3) = 0
(y +3) (y+ 3) = 0
y = –3, –3
x>y

4. I. x² – 7x + 12 = 0
II. y² + y – 12 = 0
(a) if x<y
(b) if x>y
(c) if x≤y
(d) if x≥y
(e) if x=y or no relation can be established

Ans. d
Exp. I. x² – 7x + 12 = 0
x² – 4x – 3x + 12 = 0
x (x – 4) – 3(x- 4) =0
(x -3) (x- 4) = 0
x=3,4
II. y² + y – 12 = 0
y² + 4y – 3y -12 = 0
y (y + 4) – 3(y + 4) = 0
(y – 3) (y + 4) = 0
y= 3,-4
x≥y

5. I. 2x²+ 11x + 14 = 0
II. 4y² + 12y + 9 = 0
(a) if x<y
(b) if x>y
(c) if x≤y
(d) if x≥y
(e) if x=y or no relation can be established

Ans. a
Exp. I. 2x² + 11x + 14 = 0
2x² + 4x + 7x + 14 = 0
2x (x +2) + 7(x+2) =0
(2x +7) (x+ 2) = 0
x=-7/2,-2
II. 4y² + 12y +9 = 0
4y² + 6y + 6y +9 = 0
2y (2y + 3) + 3(2y + 3) = 0
(2y + 3) (2y + 3) = 0
y= -3/2,-3/2
x<y

6. A solid sphere is melted and recast into a right circular cone with a base radius equal to the radius of the sphere. Find the ratio between height of the cone to the radius of the cone?
(a) 4 : 3
(b) 2 : 3
(c) 3 : 4
(d) 1 : 2
(e) 4 : 1

7. Speed of scooter, car and train are in the ratio of 1 : 4 : 16. Find ratio of time taken by scooter, car and train to cover certain distance?
(a) 256 : 16 : 1
(b) 1 : 4 : 16
(c) 16 : 4 : 1
(d) 16 : 1 : 4
(e) 16 : 8 : 1

8. If the selling price of a mat is five times the discount offered and percentage of discount is equal to the percentage of profit, then find the ratio of the discount offered to the cost price.
(a) 11 : 30
(b) 1 : 3
(c) 4 : 15
(d) 7 : 30
(e) 2 : 15

9. Reduction of 20% in the price of sugar enables a person to purchase 6 kg more for Rs. 240. Find the original price per kg of sugar?
(a) Rs. 10/kg
(b) Rs. 8/kg
(c) Rs. 6/kg
(d) Rs. 5/kg
(e) Rs. 12/kg

10. P can cultivate 2/5th of the land in 6 days, Q can cultivate 1/3rd of the same land in 10 days, working together P and Q can cultivate 4/5th of the land in:-
(a) 7 days
(b) 8 days
(c) 25/3 days
(d) 9 days
(e) 12 days

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