## Railway JE Quant quiz for Phase I

**Railway JE Quant quiz for (Phase I), RRB NTPC, SSC various exams and other competitive exams.**

Q1. **In given figure find the area (in cm square) of shaded regions A & B if radius of circle is 1 cm. **

A)

B)

C)

D)

Q2. **The houses on ABC lane are numbered consecutively from 1 to 49. If the sum of the numbers of the houses preceding the house numbered n is equal to the sum of the numbers of the houses following it. Then find the value of n? **

A) 40

B)35

C) 30

D) 20

Q3. **Find the value of k if the points A (3, 4), B (5, K) and C (4, -4) are collinear? **

A) K = 12

B) K = 10

C) K = -12

D) K = -10

Q4. **Applied to a bill for 36000 the difference between a discount of 30% and two successive discount of Rs. 25% and 5% is **

A) Nill

B) Rs. 450

C) Rs. 900

D) Rs. 250

Q5. **A man purchased 3 Article. A, B & C in the ratio of 6 : 4 : 5. 50% of Article A is sold at 20% loss, 25% of article B is sold at 50% loss. Find the profit percentage of remaining if he wants to make 10% profit at all the articles. (Cost price of each article of all type is same) **

A) 13 7/11%

B) 17 1/3%

C) 23 7/11%

D) 25 7/11%

Q6. **If are in AP. Find a, and also find a, b & c’s **

A)

B)

C)

D)

Q7. **A cubical block of side 7 cm is surmounted by a hemisphere of diameter equal to the side of the cube. Then find the total surface area of the solid. **

A) 332.5 sq. cm

B) 409.5 sq. cm

C) 371 sq. cm

D) 294 sq. cm

Q8.

A) 0.6

B) 8/5

C) 8/15

D) 1.2

Q9. **A canteen requires 98 kg of rice for fourteen days. The quantity of rice required for the months of February and March together is (not for leap year) **

A) 410 kg

B) 420 kg

C) 451 kg

D) 413 kg

Q10. **What is the reflection of the point (4, 1) in the line y = -2? **

A) (4, -5)

B) (4, 0)

C) (0 , -4)

D) (-4, -3)

**Solutions**

**Solutions**

**Q1. Ans(C)**

Q2. Ans(B)

Q3. Ans(C)

Since the given points are collinear the area of the triangle formed by them must be 0 i.e.

Q4. Ans(B)

Q5. Ans(C)

Q6. Ans(B)

Q7. Ans(A)

Diameter = side of the cube = 7

ATQ,

Total Surface area of solid = surface area of cube – surface area of base of hemisphere + curved surface area of hemisphere

Q8. Ans(B)

Q9. Ans(D)

Q10. Ans(A)

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