RRB NTPC Quant quiz for Stage I : 03/03/2019

RRB NTPC Quant quiz for Stage I

Railway NTPC Quant quiz for  (Phase I), RRB (JE), RRB ALP, SSC various exams and other competitive exams.

Q1. 2/5 of a number exceeds 2/7 of the same number by 40. Find the number. 

A)  250 

B) 280

C) 320

D) 350

Q2.  2/3 of 3/4 of 4/9 of 1/60 of 120 of a number will be what percentage of that number? 

A) 44.44

B) 33.33

C) 22.22

D) 11.11

Q3.   Find the value of ‘x’ (such that x > 0) which will satisfy the equation  



C) 1


Q4.  A square has a perimeter equal to 24 units. If the length of each side of the square is reduced by 2 units, then find the area (in sq units) of the square. 


B) 9

C) 16

D) 25

Q5.   If the two sides of obtuse angled triangle are 8 cm and 15 cm and the third side is x then, 

A) 7 < x < 2

B) 7 < x < √161

C) 17 < x < 21

D) Cannot be determined

Q6.  P and Q started a business by investing Rs 156000 and Rs 117000 respectively and their time period of investment is same. If P’s share in the profit earned by them is Rs 12000, then what is the total profit (in Rs) earned by both of them together? 

A)  25000 

B) 17000

C) 21000

D) 18000

Q7.  The distance between place X and Y is 720 km. An express train leaves place X at 5:00 p.m. and runs at a speed of 45 km/hr. The train stops on the way for 45 minutes. At what time (in a.m.) the train reaches at place Y?

A) 1:45

B)  9:45 

C) 7:15

D) 12:15

Q8.  If the lengths of the two parallel sides of a trapezium are 5 cm and 7 cm and its area is 24 cm². Find the distance between its parallel sides (in cm). 

A) 2

B) 4

C) 8

D) 6

Q9.  If the measure of the interior angle of a regular polygon is 60° greater than the measure of its exterior angle then how many sides does it have



C) 10


Q10.  Find the total surface area (in cm²) of a right circular cone of diameter 28 cm and slant height 12 cm. 

A) 1714

B) 1161

C) 1144 

D) 1477


Q1. Ans(D)

Q2. Ans(A)

Q3. Ans(C)

Q4. Ans(C)

Perimeter, 4a = 24 units
a = 6 units
New side, a= 6 – 2 = 4 unit
New Area = (4)²
= 16

Q5. Ans(C)

 For possible ∆,
x > 15 – 8 = 7
x > 7
for obtuse ∆,
x² + 8² < (15)²
x² < 161
x < √161 

Q6. Ans(C)

Q7. Ans(B)



Q9. ANs(D)

Q10. Ans(C)

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