# SBI PO Prelims Reasoning Ability Quiz – 28

Table of Contents

## SBI PO Prelims Reasoning Ability Quiz

Reasoning Ability is a part of almost all major competitive exams in the country and is perhaps the most scoring section also. Aspirants who regularly practice questions have a good chance of scoring well in the Reasoning Ability Section. So here we are providing you with the SBI PO Prelims Reasoning Ability Quiz to help you prepare better. This SBI PO Prelims Reasoning Ability Quiz includes all of the most recent pattern-based questions, as well as Previous Year Questions. This SBI PO Prelims Reasoning Ability Quiz is available to you at no cost. Candidates will be provided with a detailed explanation of each question in this SBI PO Prelims Reasoning Ability Quiz. Candidates must practice this SBI PO Prelims Reasoning Ability Quiz to achieve a good score in the Reasoning Ability Section.

Directions (1-5): Study the following information carefully to answer the given questions.

A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement.

Input: zone pine 38 40 gate 62 flow 61 goat loose 50 44

Step I: loose 3 zone pine 40 gate 62 flow 61 goat 50 44

Step II: loose 3 zone 20 pine gate 62 flow 61 goat 50 44

Step III: loose 3 zone 20 goat 28 pine gate 62 flow 61 50

Step IV: loose 3 zone 20 goat 28 flow 35 pine gate 62 61

Step V: loose 3 zone 20 goat 28 flow 35 pine 47 gate 62

Step VI: loose 3 zone 20 goat 28 flow 35 pine 47 gate 56

Step VI is the last step, find out in each of the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input.

Input: master 36 what 48 money boot 53 2 mess fist 60 61

1. Which of the following will be the penultimate step of the above input?

(a) Step VI

(b) Step V

(c) Step IV

(d) Step III

(e) None of these

Answer & Explanation
Ans. b

Exp.

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:

i) The machine rearranges only one word and one number in each step.

ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example loose(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged in each step in increasing order in such a way that the difference of the numerical value of the sum of the vowels in the word and that number is arranged in each step after that word. For example If 2 is arranged after boot, boot=30 – 2 = 28

Now lets take the arrangement given in the Question

Input: master 36 what 48 money boot 53 2 mess fist 60 61

Step I: boot 28 master 36 what 48 money 53 mess fist 60 61

Step II: boot 28 money 16 master what 48 53 mess fist 60 61

Step III: boot 28 money 16 fist 39 master what 53 mess 60 61

Step IV: boot 28 money 16 fist 39 master 47 what mess 60 61

Step V: boot 28 money 16 fist 39 master 47 mess 55 what 61

Step VI: boot 28 money 16 fist 39 master 47 mess 55 what 60

1. What will be the position of ‘mess’ in the last but one step?

(a) Seventh from the left

(b) Second from the right

(c) Sixth from the left

(d) Fifth from the left

(e) None of these

Answer & Explanation
Ans. e

Exp.

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:

i) The machine rearranges only one word and one number in each step.

ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example loose(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.

iii) The number are arranged in each step in increasing order in such a way that the difference of the numerical value of the sum of the vowels in the word and that number is arranged in each step after that word. For example If 2 is arranged after boot, boot=30 – 2 = 28

Now lets take the arrangement given in the Question

Input: master 36 what 48 money boot 53 2 mess fist 60 61

Step I: boot 28 master 36 what 48 money 53 mess fist 60 61

Step II: boot 28 money 16 master what 48 53 mess fist 60 61

Step III: boot 28 money 16 fist 39 master what 53 mess 60 61

Step IV: boot 28 money 16 fist 39 master 47 what mess 60 61

Step V: boot 28 money 16 fist 39 master 47 mess 55 what 61

Step VI: boot 28 money 16 fist 39 master 47 mess 55 what 60

1. Which word/number would be the fourth from the right end in Step IV?

(a) 26

(b) 78

(c) 16

(d) 36

(e) None of these

Answer & Explanation
Ans. e

Exp.

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:

i) The machine rearranges only one word and one number in each step.

ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example loose(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.

iii) The number are arranged in each step in increasing order in such a way that the difference of the numerical value of the sum of the vowels in the word and that number is arranged in each step after that word. For example If 2 is arranged after boot, boot=30 – 2 = 28

Now lets take the arrangement given in the Question

Input: master 36 what 48 money boot 53 2 mess fist 60 61

Step I: boot 28 master 36 what 48 money 53 mess fist 60 61

Step II: boot 28 money 16 master what 48 53 mess fist 60 61

Step III: boot 28 money 16 fist 39 master what 53 mess 60 61

Step IV: boot 28 money 16 fist 39 master 47 what mess 60 61

Step V: boot 28 money 16 fist 39 master 47 mess 55 what 61

Step VI: boot 28 money 16 fist 39 master 47 mess 55 what 60

1. After how many steps no further rearrangement of words is possible?

(a) Five

(b) Four

(c) Six

(d) Seven

(e) Eight

Answer & Explanation
Ans. a

Exp.

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:

i) The machine rearranges only one word and one number in each step.

ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example loose(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.

iii) The number are arranged in each step in increasing order in such a way that the difference of the numerical value of the sum of the vowels in the word and that number is arranged in each step after that word. For example If 2 is arranged after boot, boot=30 – 2 = 28

Now lets take the arrangement given in the Question

Input: master 36 what 48 money boot 53 2 mess fist 60 61

Step I: boot 28 master 36 what 48 money 53 mess fist 60 61

Step II: boot 28 money 16 master what 48 53 mess fist 60 61

Step III: boot 28 money 16 fist 39 master what 53 mess 60 61

Step IV: boot 28 money 16 fist 39 master 47 what mess 60 61

Step V: boot 28 money 16 fist 39 master 47 mess 55 what 61

Step VI: boot 28 money 16 fist 39 master 47 mess 55 what 60

1. What will be the position of mess in step VI?

(a) Sixth from right

(b) Seventh from right

(c) Seventh from left

(d) Fourth from right

(e) None of these

Answer & Explanation
Ans. d

Exp.

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:

i) The machine rearranges only one word and one number in each step.

ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example loose(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.

iii) The number are arranged in each step in increasing order in such a way that the difference of the numerical value of the sum of the vowels in the word and that number is arranged in each step after that word. For example If 2 is arranged after boot, boot=30 – 2 = 28

Now lets take the arrangement given in the Question

Input: master 36 what 48 money boot 53 2 mess fist 60 61

Step I: boot 28 master 36 what 48 money 53 mess fist 60 61

Step II: boot 28 money 16 master what 48 53 mess fist 60 61

Step III: boot 28 money 16 fist 39 master what 53 mess 60 61

Step IV: boot 28 money 16 fist 39 master 47 what mess 60 61

Step V: boot 28 money 16 fist 39 master 47 mess 55 what 61

Step VI: boot 28 money 16 fist 39 master 47 mess 55 what 60

Directions (6-10): Read the information given below carefully and answer the following questions.

In a certain language,

bottle boxes digital ” is coded as “ @T5  #X19  #I12  ”

unemployed pillow feather ” is coded as  “ @L21  @L23  #T18

governer monks independence” is coded as “ @E18  #N19  @E9

1. What will be the code for “mother”?

(a) #A18

(b) @M21

(c) @M3

(d) @H18

(e) None of these

Answer & Explanation
Ans. d

Exp.

This coding decoding question is based on the latest pattern. In this question, following logic are used to decode the code,

(i) If the total number of letters in the word is even then the first letter of the code will be @.  On the other hand, if the total number of letters in the word is odd, then the first letter of the code will be #.

(ii) If the total number of letters in the word is even than the middle alphabet which is smaller in alphabetical series among them is used as the second letter of the code.

If the total number of letters in the word is odd than the middle alphabet is used as the second letter of the code.

(iii) The numerical value of the code represents the place value of the greater letter among first and last letter in alphabetical series.

1. Which of the following words could be coded as “@A19 #O25”?

(a) Justice League

(b) Rolling Stones

(c) Suicide Squad

(d) Star Boy

(e) None of these

Answer & Explanation
Ans. d
1. What will be the code for “ rocky way”?

(a) @C25 @O6

(b) @C25 #A23

(c) #C25 #A25

(d) #C15 @O6

(e) None of these

Answer & Explanation
Ans. c
1. What will be the code for “black”?

(a) #N13

(b) @A13

(c) @N11

(d) #A11

(e) None of these

Answer & Explanation
Ans. d
1. Which of the following words could be coded as “@A5”?

(a) Disaster

(b) Relapse

(c) Weather

(d) Collapse

(e) None of these

Answer & Explanation
Ans. d

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