Speed, Time & Distance – Concepts and Formula
One of the most prevalent quantitative aptitude topics asked in government tests is speed, time, and distance. This is one of those topics that students are already aware of before they begin studying for competitive exams.
Although the concepts of speed, time, and distance remain the same, the kind of questions presented in exams may vary.
2-3 word problems related to Speed, Time, and Distance are asked in exams, but candidates may also expect questions about data sufficiency and data interpretation related to Time, Distance, and Speed topic.
So, we are providing you with concepts and formulas of the Speed, Distance, and Time topic to help you prepare properly for the upcoming exams.
When we travel from one point to another, there will be three Quantity that defines this journey – Speed, Distance and Time.
Relation between Speed, Distance and Time.
Distance = Speed X Time
Unit of Speed, distance and time
Speed – km/hr , m/s etc
Time – Seconds(s), Hour (h) etc
Distance – meter(m), kilometre(km) etc
Note : If the distance is in Km then time should be in hr and if the distance is in m(meter) then time should be in s ( second)
How to convert km/hr into m/s
Let’s suppose we want to convert 9 km/hr into m/s
We know that 1km = 1000 m and 1 h = 3600 s
How to convert m/s into km/hr
Let’s suppose we want to convert 10 m/s in km/hr
We know that 1km = 1000 m and 1 h = 3600 s
Question. Convert 18 km/hr into m/s ?
Answer. 18 km/hr = 18 x 5/18 = 5 m/s
Question. Convert 20 m/s into km/hr ?
Answer. 20 m/s = 20 x 18/5 = 72 km/hr
If the ratio of the speeds of A and B is a : b, then the ratio of the times taken by them to cover the same distance is
Question. Amit takes 21 min to reach his school from his home at the speed of 10 m/s. Next day Amit increases it speed to 15 m/s then how much time he takes to reach the school.
As distance is same in both the cases , Ratio of speed = 10 : 15 = 2:3
So, the ration of time will be = 3 : 2 ,
so, time take in scond case = 21/3 x 2 = 14 min
Distance between school and home = 21 x 60 x 10 = 12600 m
Time taken in scond case = distance / speed = 12600 / 15 = 840 sec
840 sec = 840/60 = 14 min
When distance is equal, we have T1S1 = T2S2
21 x 10 = T x 15
T = 14 min
Question A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Answer. Speed in m/s = 600/(5 x 60)= 2m/s
Speed in km/hr = 2 x 18/5 = 7.2 km/hr
Question A man covered a distance of 200 km in 4 hours on a bike. How much distance will be covered on a bicycle in 8 hours if he rides the bicycle at one-fifth the speed of the bike?
Answer. Speed of bike = 200/4 = 50 km/hr
Speed of bicycle = 50/5 = 10 km/hr
Distance covered = Speed x time = 10 x 8 = 80 km
Question A train leaves Station X at 4.10 P.M. and reaches Station Y at 7.25 P.M. The average speed of the train is 40 km/hr. What is the distance from X to Y?
Question The speeds of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. In what time does A reach the destination?
Answer Ratio of speed = 3 :4
Ratio of Time = 1/ 3 : 1/4 = 4 : 3
Let A and B take 4x and 3x minutes respectively to reach the destination.
Then, 4x – 3x = 20
x = 20 min,
Time taken by A = 4x = 80 min
Suppose a man covers a certain distance at x km / hr and an equal distance at y km / hr. Then, the average speed during the whole journey is
General formula for Average Speed
Question. Ram travels a distance of 50 km at the speed of 40 km/hr and return with the speed of 10 km/hr. What will be the average speed for whole journey ?
Answer. Wrong way (40 + 10) / 2 = 25 km/hr —- X
Time (case 1 ) = 50/40 = 1.25
Time (case 2 ) = 50/10 = 5
Question A person wishes to reach his destination 90 km away in 3 hours but for the first half of the journey his speed was 20 km/hr. His average speed for the rest of the journey should be
Answer Time taken to travel first half = 45/20 = 9/4 = 2(1/4) = 2 hr 15 min
Remaining time = 3 hr – 2 hr 15 min = 45 min = ¾ hr
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